Ok, a bit confused (I wanna get things cleared up for a PRE-test tomorrow)
Ok...
Here%26#039;s some I%26#039;m confused on (practice)
1. At time t in years, the value, V, of an investment of $1000 is given by V=1000e^0.02t. When is the investment worth $3000?
Also,
What is the nominal and effective annual rates for an account paying the stated annual interest, compounded?
3%
a) annually
b) quarterly
c) daily
d) continuously
That one I%26#039;m very confused on:-(
Also,
3. A bank pays interest at the nominal rate of 4.2% per year. What is the effective annual yield if compounding is
a) annual
b) monthly
c) continuous
THANKS SO much
and please show all work so I understand (explanation is good too!)...no magic numbers!!!
Continuous growth (exponential) help!!! THANKS!?online loan
Well as you reposted I guess you want the answers. But remember a pretest is so the teacher can judge what they need to teach you more of and it doesn%26#039;t count towards your marks.
1.
3000 = 1000e^0.02t
divide by 1000
3 = e^0.02t
take log of both sides
log 3 = 0.02t
divide by 0.02
50log3 = t
Type into calculator
t = 54.93
2.
Nominal
a) 3%
b) 3%
c) 3%
d 3%
Effective
E = (1+i/n)^n - 1
a)
E = (1+0.03/1)^1 - 1
E = 3%
b)
E = (1+0.03/4)^4 - 1
E = 3.034%
c)
E = (1+0.03/365)^365 - 1
E = 3.04%
d)
E = e^0.03 - 1
E = 3.045%
3)
Nominal
a) 4.2%
b) 4.2%
c) 4.2%
d 4.2%
Effective
E = (1+i/n)^n - 1
a)
E = (1+0.042/1)^1 - 1
E = 4.2%
b)
E = (1+0.042/12)^4 - 1
E = 4.28%
c)
E = e^0.042 - 1
E = 4.29%
Continuous growth (exponential) help!!! THANKS!?
loan
I can help you with #1.
3000 = 1000e^.02t.
3 = e^.02t
ln 3 = .02t.
t = 54.9 years.
If I knew what nominal and effective annual yields were, I%26#039;d help you with the rest, I promise I would. Sorry. :(
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